def sumDigiFifthPowers(x)
ret = 0
(1..(x.to_s.length)).each {|i|
ret += ((x % (10 ** i)) / (10 ** (i - 1))) ** 5 }
return ret
end
ans = 0
#upper bound is sumDigiFifthPowers(999999) as it is 5 digits
#nothing less than it can have the desired property
(100..354294).each {|num|
if num == sumDigiFifthPowers(num)
ans += num
end
}
print ans
Monday, August 19, 2013
Problem 30 - Re-using Ruby
I originally used Ruby on problem #4, and then recovered it...now I am using it for problem 30. Though I have not written a line of the language outside of Project Euler, I am starting to like it.
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