def gcd(a,b) { if (b == 0) { return a } else { return gcd(b, a%b) } } def numFracs(int d) { int low = d / 3 + 1 int high = d / 2 ret = 0 for (i in low..high) { if (gcd(i,d) == 1) { ++ret } } return ret } ans = 0 for (i in 4..12000) { ans += numFracs(i) } println ans
Friday, December 20, 2013
Problem 73 - Groovy
I haven't solved a problem in a while because of finals and break and such...and another reason is because I am playing with some very frustrating esolangs that have yet to bear any fruit. I decided to take a break from that and solve problem 73 in Groovy, a language which, like so many others, runs on the JVM and is very java-like.
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